SAT Math Test 4 (Difficult)

This is the fourth and final free SAT Math practice test that we offer at High School Test Prep. It is also our most challenging test, with a variety of difficult and very difficult questions. The topics covered by these questions all fall under the SAT Math category that is called Passport to Advanced Math.

Directions: Solve each problem and select the best of the answer choices provided. The use of a calculator is permitted.

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Question 1
A passenger ship left Southampton, England for the Moroccan coast. The ship travelled the first 230 miles at an average speed of 20 knots, then increased its speed for the next 345 miles to 30 knots. It travelled the remaining 598 miles at an average speed of 40 knots. What was the ship’s approximate average speed in miles per hour? (1 knot = 1.15 miles per hour)

A
36
B
38
C
40
D
42
Question 1 Explanation: 
The correct answer is (A).

In order to calculate the average speed of the trip, it is first necessary to solve for the total number of miles traveled and the total length of time traveled. Because the question asks for the average speed in miles per hour (and not knots), it is also necessary to convert all knots into miles per hour (mph).

Use the provided unit conversion to set up a general expression relating knots to mph:

$\frac{1 knot}{1.15 miles}$ $=$ $\frac{y knots}{x miles}$

where y = 20, 30, and 40:

$\frac{1 knot}{1.15 miles}$ $=$ $\frac{20 knots}{x miles}$

Solving for x:

$x$ $mph$ $=$ $20$ knots $*$ $\frac{1.15 mph}{1 knot}$ $=$ $23$ $mph$

Notice that knots cancel from the numerator and denominator leaving units of mph, which is what we are looking for; this verifies that we are on the right track towards the solution. Repeat this calculation for the other knot values to find: 30 knots = 34.5 mph; 40 knots = 46 mph.

Using the calculated mph values, we can now solve for the length of time each portion of the trip took. Recall that a total distance travelled is equal to a rate, or speed of travel, multiplied with a length of time; or: Distance = Rate * Time. Dimensional analysis is again useful to verify that the equation results in the appropriate units.

Use the distances and corresponding rates to solve for each time:

$230$ miles $=$ $\frac{23 miles}{hours}$ $*$ Time

$230$ miles $*$ $\frac{hours}{23 miles}$ $=$ $10$ $hours$

Repeat this calculation for the other times: 345 miles takes 10 hours, and 598 miles takes 13 hours.

Use the calculated values to divide the total distance traveled by the total length of time traveled to determine the overall average rate of travel:

Average speed $=$ $\frac{230 + 345 + 598 miles}{10 + 10 + 13 hours}$

$=$ $\frac{1173 miles}{33 hours}$

$≈$ $35.55 \frac{miles}{hour}$, which is approximately 36 mph
Question 2
At a certain lab, the ratio of scientists to engineers is 5:1. If 75 new team members are hired in the ratio of two engineers per scientist, the new ratio of scientists to engineers would be approximately 2:3. Approximately how many scientists currently work at the lab?

A
5
B
10
C
15
D
20
Question 2 Explanation: 
The correct answer is (B).

Currently our ratio is: $\frac{S}{E} = \frac{5}{1}$, or 5E = S.

Out of the 75 hires, for every three hires two will be engineers, and one will be a scientist. That will add 50 engineers and 25 scientists. We’re told that adding these people to the mix creates a new ratio:

$\frac{(E + 50)}{(S + 25)}$ $=$ $\frac{3}{2}$

Substitute 5E for S, and solve:

$\frac{(E + 50)}{(5E + 25)}$ $=$ $\frac{3}{2}$

2(E + 50) = 3(5E + 25)
2E + 100 = 15E + 75
100 = 15E + 75
25 = 15E
$\frac{25}{13}$ = E

1.9 = E (or approximately 2)

Since there are currently 5 scientists for every engineer, then there are approximately 10 scientists.
Question 3
In the xy-coordinate plane, a circle with center (−4, 0) is tangent to the line y = −x. What is the circumference of the circle?

A
$4\pi$
B
$2\pi \sqrt{2}$
C
$4\pi$
D
$4\pi \sqrt{2}$
Question 3 Explanation: 
The correct answer is (D).

Start by drawing a diagram to better visualize the problem.



The line y = −x makes a 45° angle with each axis in the second quadrant. Connect the center of the circle to the point of tangency on y = −x. The radius of a circle is perpendicular to its point of tangency.

Because y = -x, the magnitude, or length of two sides must be the same. We can draw a 45°-45°-90° triangle using the x-axis and y = −x. Because the circle is centered at (-4, 0), the sides must be of length 2.

Now, using our knowledge of right triangle ratios, we can find the radius (or hypotenuse of the triangle) to be 2√2.

(Recall that 45°, 45°, 90° right triangles share a side: side: hypotenuse ratio of x: x: x√2.)

Circumference $= 2 \pi r = 2 \pi * 2 \sqrt{2} = 4\pi \sqrt{2}$
Question 4
In a recent survey of two popular best-selling books, two-fifths of the 2,200 polled said they did not enjoy the second book, but did enjoy the first book. Of those, 40% were adults over 18. If three-eighths of those surveyed were adults over 18, how many adults over 18 did NOT report that they enjoyed the first book but not the second book?

A
187
B
352
C
473
D
626
Question 4 Explanation: 
The correct answer is (C).

Remember to find each category separately to keep the different numbers clear. The total number of people was 2,200.

$\frac{2}{5}$ of 2,200 = 880, so 880 of those surveyed said they did not enjoy the second book, but enjoyed the first book. Of these 880 people, 40% were adults over 18, so in this group there were 880 * 0.4 = 352 people.

It is also stated that $\frac{3}{8}$ of the 2,200 surveyed, or 825 people who are adults over 18. To find the number of adults who did not report that they enjoyed the first book but not the second, subtract the portion who did report they enjoyed the first book but not the second from the total number of adults:

825 − 352 = 473 adults.
Question 5
The initial number of elements in Set A is x, where x > 0. If the number of elements in Set A doubles every hour, which of the following represents the increase in the number of elements in Set A after exactly one day?

A
23x23
B
(223)x
C
23x24
D
(224)xx
Question 5 Explanation: 
The correct answer is (D).

To find the INCREASE in the elements, we need to subtract the original number from the final total number. Since the original amount is going to be multiplied by 2 (or doubled) 24 times, we can express this as the exponent: 224.

Thus, the final total increase will be 224x (the final total) − x, (the original number).
Question 6
The diameter of a circle is increased by 80%. By what percent is the area increased?

A
80%
B
224%
C
180%
D
325%
Question 6 Explanation: 
The correct response is (B).

This is a great question for plugging in your own values. Let’s say the value of the original diameter was 10. The original area would be:

area = πr2
area = (5)2π
area= 25π.

If the diameter increased by 80%, the new diameter would be 18, and the new area would be:

area = πr2
area= (9)2π
area = 81π.

The formula for percentage increase is: $\dfrac{New Number - Original Number}{Original Number} * 100$

The numerator is 81π − 25π = 56π.

$\dfrac{56π}{25π} * 100 = 224%$
Question 7
On a number line with points LMNOP, the ratio of LM to MN is 1, and the ratio of NO to OP is 3/4. If the length of LP is 28 and the length of MO is 13, what is the ratio of LO to MP?

A
7/18
B
13/28
C
15/28
D
20/21
Question 7 Explanation: 
The correct response is (D).

Let’s draw the number line:
SATmathQ10
Let's choose the variables x and y to help express the ratios. Right now the ratio of LO to MP is $\dfrac{2x + 3y}{x + 7y}$

If we could find the values of x and y, then we could determine the ratio.

We can set up 2 equations based on the given information:
Equation for MO: x + 3y = 13
Equation for LP: 2x + 7y = 28

We can solve Eq. #1 for x:
x = 13 – 3y

Substitute this value of x into Eq. #2:
2(13 – 3y) + 7y = 28
26 – 6y + 7y = 28
26 + y = 28
y = 2

Now we can find x:
x + 3(2) = 13
x + 6 = 13
x = 7

Now plug in the values of x = 7 and y = 2 to find the ratio:

= $\dfrac{2x + 3y}{x + 7y}$

= $\dfrac{14 + 6}{7 + 14}$

= $\dfrac{20}{21}$
Question 8
A pool that holds 35,000 cubic feet of water is being filled by a pump at a rate of 200 cubic feet per minute. At the same time, water is draining out through an open valve accidentally left open. If the pool is full in 200 minutes, how many cubic feet of water are draining out per minute?

A
5
B
15
C
25
D
35
Question 8 Explanation: 
The correct answer is (C).

Write an equation to model the situation:

$\frac{200 ft^3}{min}$(# of minutes) $-$ $\frac{x ft^3}{min}$(# of minutes) $= 35,000 $$ft^3$

Substituting 200 for the number of minutes, the unknown rate can be found:

$\frac{200 ft^3}{minutes}$$ * $$200$ $minutes$ $-$$\frac{x ft^3}{minutes}$$*$$200$ $minutes$ $= 35,000 ft^3$

Taking $200$ common:

$200(200-x) = 35,000$

Divide by 200:

$200 - x = 175$

$x = 25$ $\frac{ft^3}{min}$
Question 9
A bag contains 80% yellow marbles and 20% turquoise marbles. What is the probability, approximately, of obtaining exactly two turquoise marbles out of three randomly selected marbles?

A
3.2%
B
8%
C
9.6%
D
18%
Question 9 Explanation: 
The correct answer is (C).

The probability of getting one yellow marble is $\frac{4}{5}$.
The probability of getting one turquoise marble is $\frac{1}{5}$.
The probability of getting two turquoise marbles is $\frac{1}{5}$ * $\frac{1}{5}$.
There are 3 ways of getting these combinations:

Turquoise, Turquoise, Yellow
Turquoise, Yellow, Turquoise
Yellow, Turquoise, Turquoise

$(\frac{1}{5}) (\frac{1}{5}) (\frac{4}{5}) (3) = \frac{(1)(1)(4)(3)}{(5)(5)(5)}$

$\frac{12}{125}$ = 9.6%
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